If $3^{a}$ = $b^{2}$ , find the minimum value of a + b

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Solution

$3^{a}$ = $b^{2}$

For minimum value of a+b

Equate bases and exponents

3=b

a=2

so a+b = 3+2=5

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Similar questions

If $3^{a}$ = $b^{2}$ , find the minimum value of a + b

a^{2} + b^{2} = 34

a b = 12

3 {(a + b)}^{2} + 5 {(a - b)}^{2}

a, b \in R^{+}

E = \frac{16}{a^{2}} + \frac{b^{2}}{2} + \frac{a^{2}}{b}

a = 2, b = 3, c = 4

3 a - b + 2 c

a^{2} - b^{2} + c^{2}

a b - 3 a b c - 2 a c

a^{2} b + b c - 3 c^{3} - 2 a b c

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