Question

If $3\tan A-5\cos B=$ $\sqrt{3}$ and $B=$ ${90}^{\circ }$, find the value of $A$ in degrees.

Answer 1

$3\tan A-5\cos B=\sqrt{3}$
$3\tan A-5\cos {90}^0=\sqrt{3}$

$\tan A=\frac{\sqrt{3}}{3}$

$\tan A=\frac{1}{\sqrt{3}}$

$\tan A=\tan {30}^0$

$A={30}^{\circ }$