If 3 x-1- 7-a 7 x- 7-a 6 x- 6- - a 1-a 0Find the value

(3x 1)^7= a7 x^7+a6 x^6......a0 putting x = 1 we get RHS = a7+a6 +...+a0 so put x = 1 on LHS to get (3 1)^7= 2^7 = 128 so a7+a6 +...+a0 = 128 ...

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Addition of Polynomials

If 3 x-1∧ 7=a...

Question

If $(3 x - 1)^{7} = a_{7} x^{7} + a_{6} x^{6} + . . . . . . . . . . . . . . . a_{1} + a_{0}$ , then find the value of $a_{7} + a_{6} + . . a_{0}$

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