If (3x−4)(5x+7)=15x2−ax−28, then find the value of a.
1
- 1
- 2
None of these
(3x−4)(5x+7)=15x2−ax−28
3x(5x+7)−4(5x+7)=15x2−ax−28 15x2+21x−20x−28=15x2−ax−28 15x2+x−28=15x2−ax−28 x=−ax −a=1 So, a=−1