The correct option is D 19
Given,
3x–4y=1...(i)
5x–6y=7...(ii)
To make the coefficients of x equal, multiply equation (1) by 5 and equation (2) by 3.
Equation(1)×5⇒15x–20y=5...(iii)
Equation(2)×3⇒15x–18y=21...(iv)
(iv) - (iii)
⇒ 2y=21−5=16
⇒y=8
Substitute the value of y in (i) 3x−4×8=1
3x=33⇒x=11
⇒x+y=11+8=19