Question

If $4+7+2=281435,7+3+9=212781,6+2+7=121456$ then $8+4+6=?$

Answer 1

Analyze the given pattern

Given pattern: $4+7+2=281435,7+3+9=212781,6+2+7=121456$

By analyzing the pattern in the given sequences, we can say that

• $4\times 7=28$
• $7\times 2=14$
• $4-1=3$ is the fifth digit

Similarly, in $7+3+9=212781$

• $7\times 3=21$
• $9\times 3=27$
• $7+1=8$ is the fifth digit

$6+2+7=121456$

• $6\times 2=12$
• $7\times 2=14$
• $6-1=5$ is the fifth digit

So, $8+4+6=$

• $8\times 4=32$
• $4\times 6=24$
• $6+1=7$ is the fifth digit

Now for the last $6\mathrm{th}$ digit we have take sum of the product of all numbers taken two numbers at a time and have to consider first digit of result. let take it practically,

For the last $6\mathrm{th}$ digit

• In $4+7+2=281435$ the pattern for $6\mathrm{th}$ digit is $\left(4\times 7\right)+\left(7\times 2\right)+\left(2\times 4\right)=28+14+8=50$ (first digit$=5$$=$six digit of result)
• In $7+3+9=212781$ the pattern for $6\mathrm{th}$ digit is $\left(7\times 3\right)+\left(3\times 9\right)+\left(9\times 7\right)=21+27+63=111$ (first digit$=1$$=$six digit of result)
• In $6+2+7=121456$ the pattern for $6\mathrm{th}$ digit is $\left(6\times 2\right)+\left(2\times 7\right)+\left(7\times 6\right)=12+14+42=68$ (first digit$=1$$=$six digit of result)

Hence, six digit of answer to $8+4+6$ is given by

$\left(8\times 4\right)+\left(4\times 6\right)+\left(6\times 8\right)=32+24+48=104$ (first digit$=1$$=$six digit of result)

Therefore,

$8+4+6=322471$

Hence, $8+4+6=322471$.