If 5√5×53÷5−3/2=5a+2, the value of a is
4
5
6
8
7
5√5×535−3/2=5a+2⇒53/2×535−3/2=5a+2⇒5(32+3+32)=5a+2⇒56=5a+2⇒6=a+2∴a=4.
The least value of k which makes the roots of the equation
x2+5x+k=0imaginary is
A) 4 B) 5 C) 6 D) 7