If $8^{x - 1} = 2^{x + 3}$ , then $x$ is ________.

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $3$
Given, $8^{x - 1} = 2^{x + 3}$
LHS : $8^{x - 1} = 2^{3 (x - 1)}$
Comparing powers of RHS & LHS
Now $3 (x - 1) = x + 3$
$\Rightarrow 3 x - 3 = x + 3$
$\Rightarrow 2 x = 6$
$\Rightarrow x = 3$

Suggest Corrections

Similar questions

(x-1/2)*1/2=3/8

x/2*1/2=3/8

x/4=3/8

x=3/2

x=1.5

Why is this not correct?

If $(2 x + 3)^{2} + (2 x - 3)^{2} = (8 x + 6) (x - 1) + 22$ , then the value of ' $x$ ' is

- 8 x

4 - 2 x - x^{2}

- 32 x + 16 x^{2} + 8 x^{3}

1

0

If $2 x - \frac{1}{2 x} = 4$ , find $8 x^{3} + \frac{1}{8 x^{3}}$ .

x \neq 0

∣ ∣ ∣ ∣ \begin{matrix} x + 1 & 2 x + 1 & 3 x + 1 2 x & 4 x + 3 & 6 x + 3 4 x + 4 & 6 x + 4 & 8 x + 4 \end{matrix} ∣ ∣ ∣ ∣ = 0

x + 1

Join BYJU'S Learning Program