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Question

If A = {-1, 1}, find A×A×A.

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Solution

Here A = {-1, 1}

A×A={(1,1),(1,1),(1,1),(1,1),}

A×A×A={(1,1,1),(1,1,1),(1,1,1),(1,1,1),(1,1,1),(1,1,1),(1,1,1),(1,1,1)}


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