If A = {–1, 1}, find A × A × A.

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Solution

A={ −1,1 }

A×A×A={ −1,1 }×{ −1,1 }×{ −1,1 } ={ ( −1,−1 ),( −1,1 ),( 1,−1 ),( 1,1 ) }×{ −1,1 } ={ ( −1,−1,−1 ),( −1 ,−1,1 ),( −1,1,−1 ), ( −1, 1,1 ),( 1,−1,−1 ),( 1,−1,1 ),( 1,1,−1 ),( 1,1,1 ) }

Thus, the value of A×A×A is,

{ ( −1 , −1 , −1 ), ( −1,−1,1 ),( −1,1,−1 ),( −1,1,1 ), ( 1,−1,−1 ), ( 1,−1,1 ),( 1,1,−1 ),( 1,1,1 ) }

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