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Question

If a1, a2, a3,...,a15 are in A.P. and a1+a8+a15=15, then a2+a3+a8+a13+a14=

A
15
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B
10
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C
25
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D
33
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Solution

The correct option is C 25

If a1, a2, a3,...,a15 are in A.P., then a2=a1+d, a3=a1+2d,..., where d is the common difference.
a1+a8+a15=3a1+21d=15
a1+7d=5.

a2+a3+a8+a13+a14
=a1+d+a1+2d+a1+7d+a1+12d+a1+13d
=5a1+35d=5(a1+7d)
=5×5=25


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