a1,a2,a3.....an−1,ana1+an=a2+an−1=a3+an−2=K(letsay)
1a1an=a1+an(a1+an)a1an=1a1+an(1a1+1an)1a1an=1K(1a1+1an)
So, sum of
1a1an+1a2an−1+...1ana1=1K(1a1+1an)+1K(1a2+1an−1)+....1K(1a1+1an)=2K(1a1+1an+1a2+1an−1+...)=2a1+an(1a1+1a2+....1an)