If a1/x=b1/y=c1/zand b2=ac, then x+z=
y
2y
2xyz
None of these
Explanation for the correct option:
Find the value of x+z:
Given a1/x=b1/y=c1/zand b2=ac
Let a1/x=b1/y=c1/z=k
So, a=kx,b=ky,c=kz
Given b2=ac
⇒k2y=(kx)(kz)⇒k2y=k(x+z)⇒2y=x+z⇒x+z=2y
Hence, the correct option is (B).