If $a^{1 / m} = b^{1 / n} = c^{1 / p}$ and abc = 1 , then m + n + p is equal to

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Solution

The correct option is A
0

$\begin{matrix} a^{1 / m} = b^{1 / n} = c^{1 / p} = k (s a y) ∴ a = k^{m}, b - k^{n}, c = k^{p} G i v e n t h a t a b c = 1 \Rightarrow k^{m} . k^{n} . k^{p} = 1 \Rightarrow k (m + n + p) = k^{0} \Rightarrow m + n + p = 0. \end{matrix}$

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