The correct options are
A (A∪B)∩(A∪C)
C {1,2,3,4}
Given A={1,2,3}, B={2,4,5} and C={4,1,9}.
Then, A∪(B∩C)={1,2,3}∪({2,4,5}∩{4,1,9})
={1,2,3} ∪{4}
={1,2,3,4}.
Also, (A∪B)∩(A∪C)=({1,2,3}∪{2,4,5})∩({1,2,3}∪{4,1,9})
={1,2,3,4,5}∩{1,2,3,4,9}
={1,2,3,4}.
This property of sets A, B and C such that
A∪(B∩C)=(A∪B)∩(A∪C) is called the distributive property of sets (union over intersection).