Question

If $A=-125m^6{n}^{2}x,B=6m^{2}nx,C=-64m^6{n}^{2}x$ and $D=8m^{2}nx$, then $(A÷B)+(C÷D)$ is ________.

Answer 1

$A=-125m^6{n}^{2}xB=6m^{2}nxC=-64m^6{n}^{2}xD=8m^{2}nx\frac{A}{B}=\frac{-125}{6}\frac{m^6{n}^{2}x}{m^{2}nx}=\frac{-125}{6}{m}^{4}n\frac{C}{D}=\frac{-64m^6{n}^{2}x}{8m^{2}nx}=-8m^{4}n\frac{A}{B}+\frac{C}{D}=\frac{-125}{6}{m}^{4}n+(-8)m^{4}n=m^{4}n\left(\frac{173}{6}\right)$