For N2: V=2litre ,P=70cm,T=273K
nN2=PVRT=70∗276∗0.821∗293=7.658∗10−2
For O2:V=3litre,P=1000cm,T=273K
nO2=PVRT=100∗376∗0.821∗293=1.641∗10−2
After mixing V=5 litre, T=293K
Total mole =(7.658+16.41)∗10−2
PV=nRT
P∗5=(7.658+16.41)∗10−2∗0.821∗293
P=1.158atm
Also mole % of N2=7.658∗10−2((7.658+16.41)∗10−2)∗100=31.8%
mole % of O2=100−31.8=68.2 %
so nearest integer is 68.