If (a + 2b + c), (a –c)and (a - 2b + c) are in proportion, then.

b²= ac

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b= ac²

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b²= a²c

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b²= c

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Solution

The correct option is A
b²= ac

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Similar questions

a, b, c

\frac{a}{a + 2 b} = \frac{a - 2 b}{a - 4 c}

a, b, c

\frac{a}{a + 2 b} = \frac{a - 2 b}{a - 4 c}

If a, b, c are in continued proportion and a(b-c)=2b, prove that:

a-c = 2(a + b) / a

\frac{a}{a + 2 b} = \frac{a - 2 b}{a - 4 c}

\frac{b}{b + c} = \frac{a - b}{a - c}

a, b, c

(a + 2 b - c) (2 b + c - a) (c + a - b) = 4 a b c

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