The correct option is A 95
Given,
a4.b5=1 ...................(1)
loga(a5.b4)
=log(a5.b4)loga
=loga5+logb4loga
=5loga+4logbloga
=5+4logbloga...............(2)
Using equation (1),
a4.b5=1
loge(a4.b5)=0
4loga+5logb=0
⇒logbloga=−45
Putting this in equation (2),
5+4(−45)
95