Here,
an=5−11n …(1)
Taking n=1 in equ (1), we get
⇒a1=5−11 …(1)
⇒a1=5−11
⇒a1=−6
Now, taking n=2 in equ (1), we get
⇒a2=5−11 …(2)
⇒a2=5−22
⇒a2=−17
Now, taking n=3 in equ (1), we get
⇒a3=5−11 …(3)
⇒a3=5−33
⇒a3=−28
Now, we get the AP:-
-6, -17, -28, ….
Here, the common difference is
⇒ d = -17 - (-6)
⇒ d= -17 + 6
⇒ d= -11