If A and B are two events such that P(A) = 0.4, P(B) = 0.8 and P(BA) = 0.6, find P(A ∪ B)
0.24
0.96
0.04
none of these
P(BA)=0.6=P(A∩B)P(A) 0.6=P(A∩B)0.4 ⇒P(A∩B)=0.6×0.4 =0.24 P(A∪B)=P(A)+P(B)−P(A∩B) =0.4+0.8−0.24 =0.96