If (a – b)2 + (b – c)2 + (c – a)2 = 0, then __________.
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Solution
Given:(a−b)2+(b−c)2+(c−a)2=0 ⇒(a−b)2=0 and (b−c)2=0 and (c−a)2=0 ⇒a−b=0 and b−c=0 and c−a=0 ⇒a=b and b=c and c=a ⇒a=b=c Hence, if (a – b)2 + (b – c)2 + (c – a)2 = 0, then a = b = c.