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Second Fundamental Theorem of Calculus

If a=b2 p, b=...

Question

If a = b $^{2 p}$ , b = c $^{2 q}$ and c = a $^{2 r}$ , then pqr =?

1/8

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Solution

The correct option is A
1/8

$\begin{matrix} a = b^{2 p} = {(c^{2 q})}^{2 p} = c^{4 p q} = {(a^{2 r})}^{4 p q} = a^{8 p q r} ∴ p q r = \frac{1}{8} . \end{matrix}$

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