If a:b = 7:10 and x:y = 3:4 find out (3ay-2bx) : (5ay-bx)

1:10

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12:55

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7:19

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Solution

The correct option is B
12:55

$\frac{a}{b} = \frac{7}{10}$ ,
Let $a = 7 k_{1}$ and b= $10 k_{2}$
$\frac{x}{y} = \frac{3}{4}$ ,
Let $x = 3 k_{2}$ and y= $4 k_{2}$
Putting values of a, b, x and y in equations
= $\frac{3 (7 k_{1}) (4 k_{2}) - 2 (10 k_{1}) (3 k_{2})}{5 (7 k_{1}) (4 k_{2}) - (10 k_{1}) (3 k_{2})} = \frac{84 k_{1} k_{2} - 60 k_{1} k_{2}}{140 k_{1} k_{2} - 30 k_{1} k_{2}} = \frac{24 k_{1} k_{2}}{110 k_{1} k_{2}} = \frac{12}{55}$

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Similar questions

If a:b = 2:5 and x:y = 9:15
then the value of $\frac{5 a y - 2 b x}{7 b x - 3 a y}$

a : b = 2 : 3, x : y = 3 : 4

\frac{25 b y - 2 a x}{3 a y + 4 b x}

a : b = 2 : 3

x : y = 3 : 4,

\frac{2 a x - 25 b y}{3 a y + 4 b x}

2 x y - 3 a b + 2 b x - 3 a y

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