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Question

If (AB)Bondlength=1.32Ao ; (AA)Bondlength=2Ao ; (BB)Bondlength=1Ao the % covalent character of A-B bond can be expressed as (10x + y)% (where x and y varies from 0-9) then value of x2y2=?

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Solution

(AB) Bond length = 1.32˚A
(BB) Bond length = 1˚A
(AA) Bond length = 2˚A
Atomic radius of A=1˚A
Atomic radius of B=0.5˚A
Observed bond length = 1.32˚A
Calculated bond length of AB=1˚A+0.5˚A=1.5˚A
% covalent character = 1.321.5×100
=88%
10x+y=88%
x=8y=8
=x2y2=0

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