If a, b, c are in G.P, then
a(b2+c2) = c(b2+c2)
a(b2+c2)=c(a2+b2)
a2(b+c) = c2(a+b)
none of these
ba=cb⇒=b2a2=c2b2 ⇒b2+a2a2=c2+b2b2 ⇒b2+a2a2=c2+b2ac ∴ c(b2+a2)=a(c2+b2)