If a,b,c,d are in G.P., then (a+b)2, (b+c)2, (c+d)2 are in:
A.P.
G.P.
H.P.
None
b=ar, c=a r2, d=a r3
Then (a+b)2 = a2 (1+r)2, a2 r2(1+ r2),
(c+d)2 = a2 r4 (1+r)2
⇒ (a+b)2, (b+c)2, (c+d)2 are in G.P.