If $a : b = c : d = e : f = 1 : 2$ , then $(3 a + 5 c + 7 e) : (3 b + 5 d + 7 f)$ is equal to:

8 : 7

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2 : 1

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1 : 4

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1 : 2

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Solution

The correct option is D $1 : 2$
Given, $\frac{a}{b} = \frac{c}{d} = \frac{e}{f} = \frac{1}{2}$
$\Rightarrow b = 2 a; d = 2 c; f = 2 e$

$\Rightarrow \frac{3 a + 5 c + 7 e}{3 b + 5 d + 7 f} =$ $\frac{3 a + 5 c + 7 e}{3 \times 2 a + 5 \times 2 c + 7 \times 2 e}$

$\Rightarrow \frac{3 a + 5 c + 7 e}{3 \times 2 a + 5 \times 2 c + 7 \times 2 e} = \frac{3 a + 5 c + 7 e}{2 (3 a + 5 c + 7 e)}$ $= \frac{1}{2}$

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Similar questions

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e

\begin{matrix} C o l u m n I & C o l u m n I I A . T r i g l y c e r i d e s & 1. G a l a c t o s e B . L a c t o s e & 2. P a l m i t i c a c i d C . R N A & 3. G l y c e r o l D . β - p l e a t e d & 4. U r a c i l E . B e e w a x & 5. S e c o n d a r y s t r u c t u r e \end{matrix}

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