(4+√154−√15)⋅(4+√154+√15)=((4+√15)216−15)=16+15+8√15=31+8√15∴a=31andb=8∴a+b=39
−1[a−3{b−4(a−¯¯¯¯¯¯¯¯¯¯¯¯b−8)+4a}+10] equals
If a-2b = 15 and find a2+ 4b2 .
Mark (✓) against the correct answerIf 2A = 3B and 4B = 5C, then A : C = ?(a) 4 : 3(b) 8 : 15(c) 3 : 4(d) 15 : 8