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Question

If A=abcbcacab,abc=ATA=1, then find the value of a3+b3+c3.

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Solution

A=abcbcacab,AT=abcbcacab
given AAT=IAAT=|I|=1
or ∣ ∣abcbcacab∣ ∣2=1or∣ ∣abcbcacab∣ ∣=±1
or 3abca3b3c3=±1
or 31=a3+b3+c3
a3+b3+c3=2 or 4

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