If (a+ib)5=α+iβ then (b+ia)5 is equal to
Solution: (a+ib)5=α+iβ Taking complex conjugate (a−ib)5=α−iβ (−i2a−ib)5=α−iβ (−i)5(b+ai)5=α−iβ (b+ai)5=−αi+β =α i+β