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Question

If an is the nth of an A.P. such that a2+a7a4=11 and a3+a8=24, then

A
commom difference is 2
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B
first term is 2
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C
a7=14
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D
a10=21
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Solution

The correct options are
A commom difference is 2
D a10=21
Let a1=a and common difference be d,
Now,
a2+a7a4=11(a+d)+(a+6d)(a+3d)=11a+4d=11(1)

a3+a8=24(a+2d)+(a+7d)=242a+9d=24(2)

By solving both the equations, we get :
a=3, d=2a7=3+6×2=15a10=3+9×2=21


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