If $A B$ is a chord of a circle with center $O,$ and $A C = B C$ , then $x = 90^{\circ}$ .

True

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False

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Solution

The correct option is A
True

We know that the segment joining the centre of a circle and the midpoint of its chord is perpendicular to the chord.
Hence, $x = 90^{\circ}$ .

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If $A B$ is a chord of a circle with center $O,$ and $A C = B C$ , then $x = 90^{\circ}$ .

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If AB is a chord of a circle with center O, and AC=BC, then x=90∘.

The correct option is A True We know that the segment joining the centre of a circle and the midpoint of its chord is perpendicular to the chord. Hence, x=90∘.

If $A B$ is a chord of a circle with center $O,$ and $A C = B C$ , then $x = 90^{\circ}$ .

The correct option is A
True

We know that the segment joining the centre of a circle and the midpoint of its chord is perpendicular to the chord.
Hence, $x = 90^{\circ}$ .