Ifa.i=4,then(axj).(2j-3k)isequalto?
12
2
0
-12
Finding the value:
Given,
(a.j)×(2j-3k)
We can write,
a.(j×2j-3k)=a.(-3j×k)=-(a.i)=-3(4)=-12
Hence, option(D) is correct.