wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits a photon of wavelength λ. When it jumps from the 4th orbit to the 3rd orbit, the corresponding wavelength of the photon will be

A
2013λ
loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1625λ
loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
916λ
loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
207λ
loader
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 207λ
Wavelength of emitted photon,
1λ=R(1n221n21)
Transition from n1=3 to n2=2:
1λ=R(122132)=5R36_____(1)
Transition from n1=4 to n2=3
1λ=R(132142)=7R144 ____(2)
Dividing (1) by (2), we get
λλ=5R/367R/144=207
λ=207λ

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon
footer-image