The given vectors a → , b → and c → are unit vectors and a → + b → + c → =0.
Now,
| a → + b → + c → | 2 =0 ( a → + b → + c → )⋅( a → + b → + c → )=0 | a → | 2 + | b → | 2 + | c → | 2 +2( a → ⋅ b → + b → ⋅ c → + c → ⋅ a → )=0
Substitute the values of | a → |, | b → | and | c → | in the above equation.
1 2 + 1 2 + 1 2 +2( a → ⋅ b → + b → ⋅ c → + c → ⋅ a → )=0 3+2( a → ⋅ b → + b → ⋅ c → + c → ⋅ a → )=0 ( a → ⋅ b → + b → ⋅ c → + c → ⋅ a → )= −3 2
Thus, the value of ( a → ⋅ b → + b → ⋅ c → + c → ⋅ a → ) is −3 2 .
If a, b, c are unit vectors such that a + b + c = 0, then find the value of a.b + b.c + c.a