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Question

If ∣ ∣ ∣2x2+x3x54x+3x+5x26x62x35x+63x∣ ∣ ∣=ax5+bx4+cx3+dx2+ex+f xR, then the value of f is

A
14
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B
5
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C
0
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D
8
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Solution

The correct option is C 0
As, the given expression is true for all x.
Put x=0 on both sides, we get
f=∣ ∣053506360∣ ∣
f is a skew-symmetric determinant of odd order.
f=0
( determinant of odd order skew-symmetric matrix is 0)

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