If ∣∣ ∣∣a−b−c2a2a2bb−c−a2b2c2cc−a−b∣∣ ∣∣ =(a+b+c)(x+a+b+c)2, x≠0 and a+b+c≠0, then x is equal to :
∣∣ ∣∣a−b−c2a2a2bb−c−a2b2c2cc−a−b∣∣ ∣∣=(a+b+c)3
∣∣ ∣∣x+y+2zxyzy+z+2xyzxz+x+2y∣∣ ∣∣=2(x+y+z)3