If 13log 3 M -3log 3 N -1-log 0-006 5- then

The correct option is B N^9=9M ...

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First Fundamental Theorem of Calculus

If 13log 3 ...

Question

If $\frac{1}{3} {log}_{3} M + 3 {log}_{3} N = 1 + {log}_{0.006} 5$ , then

M^{9} = \frac{9}{N}

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N^{9} = \frac{9}{M}

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M^{9} = \frac{3}{N}

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N^{9} = \frac{3}{M}

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