If cos4A – sin4A = 35, then 2cos2A−1= ?
We know sin2A + cos2A = 1 and a2 - b2 = (a+b) (a-b)
Using the two identities, we have cos4A - sin4A = (cos2A - sin2A) (sin2A + cos2A) = (2 cos2A - 1) × 1 = 35
If cos4A – sin4A = 35, then 2cos2A–1=?