If cosec A + cot A=11/2 then find tan A

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cosec A + cot A =

\frac{11}{2}

tan A

If $c o s e c θ + c o t θ = \frac{11}{2}$ , then $t a n θ =$

(t a n A + c o s e c B)^{2} - (c o t B - s e c A)^{2} = 2 t a n A c o t B (c o s e c A + s e c B)

If $c o s e c A + c o t A = \frac{11}{2}$ , then tan A =

tan A + cot A = m cosec 2 A

m

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