If cot A+2 tan A=tan B then cot A is
2 tan(A−B)
2 tan(B−A)
2 tan(A+B)
−2 tan(A+B)
cot A+2 tan A=tan B ----1
Adding cot A on both sides
2(cot A+tan A)=tan B+cot A
from (1) 2(tan B−tan A)=tan B+cot A
2(tan B−tan A)tan A tan B+1=1tan A∴2 tan(B−A)=cot A.
If tan A=2tanB+cotB, then 2tan(A-B)=