wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If Δ1 = ∣ ∣ ∣a21+b1+c1a1a2+b2+c2a1a3+b3+c3b1b2+c1b22+c2b2b3+c3c3c1c3c2c23∣ ∣ ∣ and Δ2 = ∣ ∣a1b1c1a2b2c2a3b3c3∣ ∣ , then Δ1Δ2 is equal to

A
a1b2c3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
a1a2a3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a3b2c1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a1b1c1+a2b2c2+a3b3c3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A a1b2c3
Δ1 = ∣ ∣ ∣a21+b1+c1a1a2+b2+c2a1a3+b3+c3b1b2+c1b22+c2b2b3+c3c3c1c3c2c23∣ ∣ ∣

Taking c3 common from R3
Δ1=c3∣ ∣ ∣a21+b1+c1a1a2+b2+c2a1a3+b3+c3b1b2+c1b22+c2b2b3+c3c1c2c3∣ ∣ ∣
R2R2R3
=c3∣ ∣ ∣a21+b1+c1a1a2+b2+c2a1a3+b3+c3b1b2b22b2b3c1c2c3∣ ∣ ∣
Taking b2 common from R2
=b2c3∣ ∣ ∣a21+b1+c1a1a2+b2+c2a1a3+b3+c3b1b2b3c1c2c3∣ ∣ ∣
R1R1(R2+R3)
=b2c3∣ ∣ ∣a21a1a2a1a3b1b2b3c1c2c3∣ ∣ ∣
Taking a1 common from R1
=a1b2c3∣ ∣a1a2a3b1b2b3c1c2c3∣ ∣
Δ1=a1b2c3Δ2

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon