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Question

If Δ=∣ ∣11111+x1111+y∣ ∣ for x0,y0 then Δ is

A
Divisible by neither x nor y
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B
Divisible by both x and y
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C
Divisible by x but not y
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D
Divisible by y but not x
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Solution

The correct option is B Divisible by both x and y
Δ=∣ ∣11111+x1111+y∣ ∣
Δ=(1+x)(1+y)11(1+y1)+1(11x)
Δ=(1+x)(1+y)1yx
Δ=xy+1+x+y1yx
Δ=xy
It is divisible by both x and y
B is correct.


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