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Question

If 3713=2+1x+1y+1z, where x,y,z are integers, then the value of x+y+z is

A
6
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B
8
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C
7
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D
2
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Solution

The correct option is A 8
3713=2+1x+1y+1z.....(1)
373 can also be written as-
3713
=2+1(1311)
=2+11+1(112)
=2+11+15+12.....(2)
On comparing eqn(1)&(2), we get
x=1
y=5
z=2
x+y+z=1+5+2=8
Hence the correct answer is 8.

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