Solving Inequalities with Unknowns in the Denominator
If 5x+32x≤ 26...
Question
If 5x+32x≤26,x>0, then
A
x≥14
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B
0<x≤14
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C
0<x<14
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Solution
The correct option is Ax≥14 We know that x > 0, ⇒ We can multiply both sides of the inequality by 2x without flipping the inequality sign.
Multiplying both sides by 2x ⇒10+3≤52x
Now, dividing both sides by 52 ⇒52x≥13 ⇒x≥14