If p-3a-5b- - q-2a-b- - r-a-4b- - s-a-b- are four vectors such that sin p-q- -1 and sin r-s- -1 then cos a-b- is -

The correct option is D 195√(43) sin(p⃗∧ #160;q⃗) = 1 . #160; ⇒ #160;the angle between #160; p⃗ #160;and #160; q⃗ #160;i ...

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Applications of Dot Product

If p⃗=3a⃗-5...

Question

If $\to p = 3 \to a - 5 \to b; \to q = 2 \to a + \to b; \to r = \to a + 4 \to b; \to s = - \to a + \to b$ are four vectors such that $sin (\to p \land \to q) = 1$ and $sin (\to r \land \to s) = 1$ then $cos (\to a \land \to b)$ is :

- \frac{19}{5 \sqrt{43}}

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\frac{19}{5 \sqrt{43}}

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\to a, \to b, \to c

\to p = \to a - 2 \to b + 3 \to c

\to q = 2 \to a - 3 \to b + 4 \to c

\to r = 3 \to a - 4 \to b + 5 \to c

\to s = 7 \to a - 11 \to b + 15 \to c .

\to p = 5 \to a - 3 \to b; \to q = - \to a - 2 \to b

\to r = - 4 \to a - \to b; \to s = - \to a + \to b

\to x = \frac{1}{3} (\to p + \to r + \to s)

\to y = \frac{1}{5} (\to r + \to s)

\to a, \to b, \to c

\to p = \frac{\to b \times \to c}{[\to a \to b \to c]}

\to q = \frac{\to c \times \to a}{[\to a \to b \to c]}

\to r = \frac{\to a \times \to b}{[\to a \to b \to c]}

(2 \to a + 3 \to b + 4 \to c) . \to p + (2 \to b + 3 \to c + 4 \to a) . \to q +

(2 \to c + 3 \to a + 4 \to b) . \to r =

\to a, \to b, \to c

\to p, \to q, \to r

(\to a \times \to p) + (\to b \times \to q) + (\to c \times \to r)

\to a, \to b

\to c

\to p, \to q

\to r

\to p = \to a + \to b - 2 \to c, \to q = 3 \to a - 2 \to b + \to c

\to r = \to a - 4 \to b + 2 \to c

\to a, \to b

\to c

V_{1}

\to p, \to q

\to r

V_{2}

V_{2} : V_{1} =

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