If equation sin 4 x -1-tan 8 x then x isA- -B- - - 2C- - - 6D- - - 4

The correct option is A sin^4x = 1 + tan^8x only when nbsp; sin^4x = 1 and 1 + nbsp;tan^8x = 1 ⇒ nbsp;sin^2x = 1 and 1 + nbsp;tan^8x = 0 Which is neve ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Basic Trigonometric Identities

If equation s...

Question

If equation $s i n^{4} x = 1 + t a n^{8} x$ then x is

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

π/2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

π/6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

π/4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A

$s i n^{4} x = 1 + t a n^{8} x$ only when

$s i n^{4} x = 1 a n d 1 + t a n^{8} x = 1$

$\Rightarrow$ $s i n^{2} x = 1 a n d 1 + t a n^{8} x = 0$

Which is never possible since sinx and tanx vanish simultaneously

Suggest Corrections

Similar questions

Q. The smallest value of x satisfying the equation

\sqrt{3} (\cot x + \tan x) = 4

is
(a)

2 π / 3

(b)

π / 3

(c)

π / 6

(d)

π / 12

In a $△$ ABC, a=1 and the perimeter is six times the A.M of the sines of the angles then measure of $∠ A$ is

Q. If

t a n A = \frac{a}{a + 1}

and

t a n B = \frac{1}{2 a + 1},

then tha value of A+B is

Q. For the curve y = 3sin

θ c o s θ, x = e^{θ} s i n θ, 0 \leq θ \leq π

; tangent is parallel to x-axis, then

θ

Q. The smallest value of θ satisfying the equation

\sqrt{3} (\cot θ + \tan θ) = 4

is
(a)

2 π / 3

(b)

π / 3

(c)

π / 6

(d)

π / 12

Join BYJU'S Learning Program

If equation sin4x=1+tan8x then x is

The correct option is A sin4x=1+tan8x only when sin4x=1and 1+tan8x=1 ⇒ sin2x=1and 1+tan8x=0 Which is never possible since sinx and tanx vanish simultaneously

If equation $s i n^{4} x = 1 + t a n^{8} x$ then x is

The correct option is A

$s i n^{4} x = 1 + t a n^{8} x$ only when

$s i n^{4} x = 1 a n d 1 + t a n^{8} x = 1$

$\Rightarrow$ $s i n^{2} x = 1 a n d 1 + t a n^{8} x = 0$

Which is never possible since sinx and tanx vanish simultaneously