If f:N→N be a function defined by f(x) = x2 + x, then find f(-2).f(2) + f(3).
f:N→N is a function defined by f(x) = x2 + x
f(-2) = (−2)2 + (-2) = 4 – 2 = 2
f(2)= 22 + 2 = 4 + 2 = 6
f(3) = 32 + 3 = 12
f(-2).f(2) + f(3) = 2 × 6 + 12 = 24