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Question

If f : R → R be given by for all fx=4x4x+2 x ∈ R, then

(a) f(x) = f(1 − x)
(b) f(x) + f(1 − x) = 0
(c) f(x) + f(1 − x) = 1
(d) f(x) + f(x − 1) = 1

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Solution

(c) f(x) + f(1 − x) = 1

fx=4x4x+2 ; x ∈ R
f (1-x) = 41-x41-x+2= 42×4x+4=24x+2f(x) +f(1-x) = 4x4x+2+24x+2 = 4x+24x+2 =1

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